Specific Heat Capacity Homework Answers

Specific Heat Capacity Homework Answers

Specific heat capacity is a physical property that measures how much heat energy is needed to change the temperature of a substance by a certain amount. It is usually denoted by the symbol c or s, and has the unit of joules per kilogram per degree Celsius (J/kgC) or joules per kilogram per kelvin (J/kgK). The specific heat capacity of a substance depends on its chemical composition, its state of matter, and the temperature and pressure it is under.

In this article, we will provide some examples of homework questions and answers related to specific heat capacity. We will also explain how to use the formula for specific heat capacity to solve problems involving heat transfer and temperature change.

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Example 1: Calculating Specific Heat Capacity

Question: A piece of iron with a mass of 50 g is heated from 20C to 100C by absorbing 837 J of heat energy. What is the specific heat capacity of iron?

Answer: To find the specific heat capacity of iron, we need to use the formula:

c = Q / (m * ΔT)

where c is the specific heat capacity, Q is the heat energy transferred, m is the mass of the substance, and ΔT is the change in temperature. Plugging in the given values, we get:

c = 837 / (50 * 80) c = 0.209 J/gC

Therefore, the specific heat capacity of iron is 0.209 J/gC.

Example 2: Calculating Heat Energy Transferred

Question: A cup of water with a mass of 200 g and a temperature of 25C is placed in a microwave oven that delivers 800 W of power for 2 minutes. How much heat energy is transferred to the water? What is the final temperature of the water? Assume that the specific heat capacity of water is 4.18 J/gC and that all the microwave energy is absorbed by the water.

Answer: To find the heat energy transferred to the water, we need to multiply the power of the microwave by the time it is on:

Q = P * t Q = 800 * 120 Q = 96000 J

To find the final temperature of the water, we need to rearrange the formula for specific heat capacity and solve for ΔT:

ΔT = Q / (m * c) ΔT = 96000 / (200 * 4.18) ΔT = 114.83C

The final temperature of the water is then obtained by adding ΔT to the initial temperature:

Tf = Ti + ΔT Tf = 25 + 114.83 Tf = 139.83C

Therefore, the heat energy transferred to the water is 96000 J and the final temperature of the water is 139.83C.

Example 3: Calculating Mass of Substance

Question: A metal block with an unknown mass and a specific heat capacity of 0.5 J/gC absorbs 500 J of heat energy when its temperature increases from 10C to 30C. What is the mass of the metal block?

Answer: To find the mass of the metal block, we need to rearrange the formula for specific heat capacity and solve for m:

m = Q / (c * ΔT) m = 500 / (0.5 * 20) m = 50 g

Therefore, the mass of the metal block is 50 g.